Maximum number of equivalence relations on set $A = \{1, 2, 3, 4\}$ is $N$, then -
$14 \leq N \leq 20$
$21 \leq N \leq 28$
$29 \leq N \leq 36$
$N \geq 37$
Solution set of $x \equiv 3$ (mod $7$), $p \in Z,$ is given by
Show that the number of equivalence relation in the set $\{1,2,3\} $ containing $(1,2)$ and $(2,1)$ is two.
The relation $R$ defined on the set $A = \{1, 2, 3, 4, 5\}$ by $R = \{(x, y)$ : $|{x^2} - {y^2}| < 16\} $ is given by
A relation from $P$ to $Q$ is
Let $R = \{(a, a)\}$ be a relation on a set $A$. Then $R$ is